Explanation:

Let's begin by explaining that the Work done by a Force refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a distance . When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:

(1)

In the case of this rectangular aquarium (see figure attached), we know its initial volume (which is the same volume occupied by water, because the tank is full) is:

(2)

In addition, we know the force needed to pump a small amount of water is:

(3)

On the other hand, we know the density of the water is given by the following equation:

(4)

Where is the mass of water and is the volume of a thin "sheet" of water.

Finding :

(5)

Substituting (5) in (3):

(6)

And substituting (6) in (1):

(7)

Now, we are asked to find the work needed to pump half of the water out of the aquarium. So, if the aquarium is deep, the half is :

(8)

(9)

Well, in order to solve this, we have to write the definite integral from y=0 mto y=0.5m:

(10)

Knowing :

(11)

(12)

>>>>This is the work needed to pump half of the water out of the aquarium

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!

the answer should be in the picture.